Source: Official Guide Revised GRE 2nd Ed. Part 9; Section 5; #2
Raafe Khan
If you compare using the box method we will get
x^2 +1 [] x^+1
then subtract one from both sides
x^2 [] x^3
Multiply both sides by 1/(x^2)
1 [] x
Since x<1 ; The answer is A
Oct 25, 2014 • Comment
Jonathan , Magoosh Tutor
Nice job! It's fine to multiply both sides by 1/(x^2) because we know that's a positive quantity.
Jun 29, 2015 • Reply
Chris Lele, Magoosh Tutor
Dec 8, 2012 • Comment
PRATHIBHA AMAND
sir when x=0 , is it right to cancel the terms by x2
Jun 26, 2015 • Reply
Actually we CAN cancel by x^2 here, because we know x^2 is positive. We wouldn't be able to cancel if we had a potentially negative value, however.
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